t^2=0.15

Solution for t^2=0.15 equation:

t^2=0.15

We move all terms to the left:

t^2-(0.15)=0

We add all the numbers together, and all the variables

t^2-0.15=0

a = 1; b = 0; c = -0.15;
Δ = b2-4ac
Δ = 02-4·1·(-0.15)
Δ = 0.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.6}}{2*1}=\frac{0-\sqrt{0.6}}{2}
=-\frac{\sqrt{}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.6}}{2*1}=\frac{0+\sqrt{0.6}}{2}
=\frac{\sqrt{}}{2}
$